The area of a parallelogram is A = bh. Solve for h (height) in this formula.
You have h defined in the equation, now you must isolate it.
well if a=bh, then you divide both sides by b, which gives you \(\large\frac{a}{b}=h\), or \(h=\large\frac{a}{b}\). Does that make sense? @mathematicshead ? Next problem I want you to try on your own. :)
& hows that @Anickyan
well @Anickyan has stated, h is right there in the equation. it is not 2h, h^2, just h. all you had to do was get it by itself
What Jamierox4ev3r said. Try to do it with this equation, just to practice a bit: \[2a + 3 = \frac{ h }{ b } - 5\] Solve for h
hello @mathematicshead ? what should you do to get the fraction \(\Large\frac{h}{b}\) by itself? Think now, and whatever you do must be done to both sides.
i dont understand any of this at all, thats why im on here
You should have listened in class. And if your teacher is assigning you this work, and haven't taught you it yet, you'd probably better talk to him/her.
well think about how you would solve a regular equation. When faced with an equation, just see if you can add or subtract the sides :) for example : x+2=8 -2 -2 ------- x=6
@mathematicshead watch my process carefully and see if you understand: \(2a+3=\large\frac{h}{b}-5\) +5 +5 ----------------- 2a+8=\(\frac{h}{b}\) multiply \(\large\frac{h}{b}\) by b and everything by b and you get : 2ab+8b=h
hey you guys there? O_O @mathematicshead and @Anickyan ?
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Yes. mathematicshead, this is really basic algebra. How old are you, and what grade are you in?
@mathematicshead ^
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