Question

Is this correct?

y=-2(x+1)^2+4

- reflects x axis, shifts 1 left, up 4, and has a verticle compression??

Answer 1

looks right

Answer 2

y = (x)^2

y = -(x)^2 , reflects

y = -2(x)^2, this makes things longer in the vertical so im leary of the vertical "compression"; but then im out of date with the terminology

y = -2(x+1)^2 , left by 1

y = -2(x+1)^2+4 , up by 4

Answer 3

vertical stretch does seem more appropriate

http://regentsprep.org/Regents/math/algtrig/ATP9/funclesson1.htm

Answer 4

thank you so much for helping!

Answer 5

so when is it verticle stretch or compression? ):

Answer 6

that's where I get confused

Answer 7

when we multiply by some constant whose absolute value is greater than 1

|-2| > 1

we are moving the points further away from the x axis.

y=x; when x=1, y=1
y=2x; when x=1, y=2

y=2 is further away from the x axis then y=1

Answer 8

when we mutiply by a constant that is a proper fraction; we are essentially dividing ... and lessening the distance

Answer 9

y=x, when x=1, y=1
y=1/2 x, when x=1, y=1/2

notice that y=1/2 is closer to the x axis than y=1

Answer 10

compression is moving things closer, stretching moves them further away ..

Answer 11

so... than this problem is compression, no? .__.

Answer 12

compare it:

y = x^2

y = -2x^2

for any value of x (other than 0 in this case), how does that effect the y value?

Answer 13

.... D: idk :(

Answer 14

the closer it is to 1, the skinnier the graph gets?