Question

y=2x^2+4x-8
The axis of symmetry is the line x = ____.

Answer 1

find the vertex for it, usually you could find it with \(\bf \left(-\cfrac{b}{2a}, c-\cfrac{b^2}{4a}\right)\)

so the "x" coordinate off the pair, will be the value for the axis of symmetry

Answer 2

what is the answer i will give you a meadl @jdoe0001

Answer 3

well, what is it? yeah, well, you tell me :)
we help by clearing out some things folks may be off about
not by getting answers so they can transcribe them

Answer 4

I mean, using the \(\bf \left(-\cfrac{b}{2a}, c-\cfrac{b^2}{4a}\right)\)
can't get simpler than that

Answer 5

you can also find the answer by converting the equation in vertex form

Answer 6

y=2x^2+4x-8
y = 2(x^2 + 2x - 4)
= 2(x + 1)^2 - 5)
= 2 (x + 1)^2 - 10

this is the vertex form
te value of x corresponding to the vertex is when x + 1 = 0
- now you can find the line of symmetry

Answer 7

hmmm, I'd not bother, he just wanted it done for him

Answer 8

yea i know but i'm hoping i might cajole him into trying to do something for himself

Answer 9

he's gone anyway!!!!

Answer 10

if he's not going to use a simple equation like the one I posted, very unlikely he'd do a square completion, some folks just misundertand the meaning of "help", sadly

Answer 11

yea - i guess you are right - i just thought i'd try...