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@ankit042 @Anickyan @DebbieG
Replace f(x) with y. Then solve for x.
Replace \(f(x)\) with \(y\), like this: \(y = \frac{3x - 2}{6}\). Then solve for \(x\).
\(f(x) = \dfrac{3x - 2}{6} \) \(y = \dfrac{3x - 2}{6} \) Now, do you know how to solve this equation for x?
First, multiply both sides by 6. Then, add 2 to both sides. Finally, divide both sides by 3. What do you get for x?
@mathstudent55 i got 7/10
@mathstudent55 do you think its right?
@Anickyan can you check my answer
@romanortiz65, I got this: \[f⁻¹(y) = \frac{6y + 2}{3}\]
ohh okay
Try doing it on paper.
@Anickyan can you check my answer
This is how you do it following the steps I listed above: \(y = \dfrac{3x - 2}{6} \) First, multiply both sides by 6. \(6y = 3x - 2 \) Then, add 2 to both sides. \(6y + 2 = 3x \) Finally, divide both sides by 3. \(2y + \dfrac{2}{3} = x \) \(x = 2y + \dfrac{2}{3} \) \(f^{-1}(y) = 2y + \dfrac{2}{3} \)
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