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Simplify: a^(x/2) (y^[2-x]^(1/2) over a^(4x)y^(-2x)
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\[\frac{ r ^{s} }{ r ^{t} }=r ^{s-t}\]
i'm confused?
use this property with the a terms (same base). then use the following property to move the y term up \[\frac{ 1 }{y^{-2x} }= y^{2x}\]
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