Given F(x) shown below, complete the equation for the inverse of F(x). If necessary, use the slash mark (/) for the division symbol.
\[F(x)=\frac{ 2x }{ 7+4 }\]
\[f ^{-1}(y)=\]
@Luigi0210 @Anickyan i really lost on this problem
Oh, fun one :)
\(y = \frac{2x}{7 + 4}\) solve for \(x\)
x+2/11?
Nope. \(2x\) means \(2 * x\)
so 2+x/11
is the^ right
No. Do you want me to keep on explaining or give you the answer?
@Anickyan
what very u think is best for me
I think explaining it the best thing. I can give you some easy tasks to do: http://www.sosmath.com/algebra/solve/solve0/solve0.html They start easy, and get more and more difficult.
damn thats really hard
hey can u help
@Anickyan @Luigi0210
@Anickyan Already explained it..
i keep on getting 2+x/11
i give up its hard
@mathstudent55 can u check mt answer
You have \(F(x)=\dfrac{ 2x }{ 7+4 }\) which is really just \(F(x)=\dfrac{ 2x }{ 11 }\) Replace the F(x) with y: \(y=\dfrac{ 2x }{ 11 }\) Now solve it for x.
You should NOT get getting \(y=2+\dfrac{ x }{ 11 }\) In fact, you should be getting x={some stuff involving y|
The inverse of f(x) should be written as \[f ^{-1} (x)\]
So the question is stated incorrectly.
@kropot72 , I agree but we had a big thread about this yesterday, lol. @romanortiz65 's instructor apparently uses different notation.
x-2/11?
@kropot72 this will explain it: http://openstudy.com/study#/updates/521b8fdbe4b06211a67d369e
@romanortiz65 you have \(y=\dfrac{ 2x }{ 11 }\) And you need to solve for x. what is STEP 1. Tell the first thing you will do.
switch y and x
That isn't how you "solve for x". You solve for x by isolating x, getting it all alone.
oh x+2/11
Again, you should have x ALONE. and it should be = something. I'm not sure why you are giving responses that are not equations, and that don't isolate x. x is not involved in any sums/differences, so it isn't likely that you need any sums/differences in the inverse.
Look at the equation this way: \(y=\dfrac{ 2x }{ 11 }\) is the same as \(y=x\cdot\dfrac{ 2 }{ 11 }\) Now how do you solve that for x? How can you get that x= all alone on the RHS of the equation?
HINT: IF \(t=r\cdot\dfrac{ 5 }{ 13 }\) THEN \(\dfrac{ 13 }{ 5 }\cdot t=r\)
-x -x both sides
@DebbieG
y=13/5?
@Luigi0210 check answer
@hba check anwer please
Where are your variables..?
can u just please just give me the answer im running super late for school please
You have \(y=x\cdot\dfrac{ 2 }{ 11 }\) Read my hint above. You can multiply both sides by the reciprocal of 2/11:
\(y=x\cdot\dfrac{ 2 }{ 11 }\) \(\dfrac{ 11 }{ 2 }\cdot y=x\cdot\dfrac{ 2 }{ 11 }\cdot\dfrac{ 11 }{ 2 }\) What do you get?
@incognito, if you read above and follow the link to the prior question, you'll see the explanation about his instructor wanting the inverse as a function of y, not of x.
x x 22/22
@romanortiz65 I don't even know what you mean by that. where is your y?? Where is your = sign?
just give me final answer running late for my senior picture
please
Oh, ok.... I think you mean that's the RHS?? I guess so. But not sure why you have an extra x.
Dude.. it's just one question. It's not like you're gonna die or fail if you don't answer it.
I pretty much did. Just simplify that RHS above and you will have x=???
y=22/22
Well then..
HOW does.... \(\dfrac{ 11 }{ 2 }\cdot y=x\cdot\dfrac{ 2 }{ 11 }\cdot\dfrac{ 11 }{ 2 }\) Simplify to y=22/22??? 1. Where did the fraction go from the LHS?? 2. Where did the x go from the RHS?? 3. 22/22 is not simplified. It can be made simpler!! C'mon, man, you are psyching yourself out. You're so convinced that you can't do this that you aren't thinking it through.
11/11
1
\[\dfrac{\cancel 2 }{ \cancel {11} }\cdot\dfrac{\cancel {11} }{\cancel 2 }=1\]
i got this one wrong ;( didnt pass my test
@DebbieG the ?s u helped me were wrongg
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