Question

How do i solve this equation and check for extraneous solutions?

Answer 1

4x+3=9+2x. -3 from both sides

Answer 2

\[\sqrt[3]{4x-2}=2\sqrt[3]{x+6}\]

Answer 3

i'm sorry. this was the kind of problem I was working on.

Answer 4

x=3 and x=-2

Answer 5

Can you explain to me how you did that? @kathy0514

Answer 6

separate it into 2 equations when there is an absolute value
4x+3=±(9+2x)

solve
4x+3 = 9+2x
and
4x+3 = -(9+2x)

Answer 7

x=4 does not work

Answer 8

ust get x by itself by combining like terms
example:
3x-1 = 5
add 1 to both sides to move 1 to right side
divide by 3 to both sides to move 3 to right side

Answer 9

combine the "x" terms

Answer 10

move 2x to left side

Answer 11

you added , always do the inverse(opposite) operation

Answer 12

4x = 6 +2x --> subtract 2x

4x = 6-2x --> add 2x

Answer 13

same reason you took -3 from both sides earlier ....to cancel the 3 on right side
now take "-2x" to cancel the 2x on right side

Answer 14

4x+3 = -(9+2x)
distribute
4x+3 = -9 -2x
-3 to both sides
4x = -12 -2x
2x to both sides
6x = -12
divide
x = -2

Answer 15

don't forget to distribute the negative

Answer 16

understood?

Answer 17

one question that i have is how did you get 4x+3=9+2x

Answer 18

but yes and Thankyou

Answer 19

@kathy0514

Answer 20

x=2

-4x+3=2x-9
-2x -2x
-6x+3=-9
-3 -3
-6x=-12 / -6 = 2 x=2

Answer 21

ok good. have a great day

Answer 22

Tanks you too

Answer 23

thanks

Answer 24

I'm sorry but while I was reviewing the question again. I can't find out how you got 4x+3 insted of 4x-2

Answer 25

@kathy0514

Answer 26

x=2

-4x+3=2x-9
-2x -2x
-6x+3=-9
-3 -3
-6x=-12 / -6 = 2 x=2

Answer 27

Okay, thanks