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The equation of a curve is\[3x^2 −4xy+y^2 = 45\] Show that there are no points on the curve at which the gradient is 1.
I found \[\frac{ dy }{ dx }=\frac{ 4y-6x }{ 2y-4x }\]
set the expression for the gradient equal to one and see if it leads to a contradiction
How do you show for the contradiction when you get x=y
now plug y=x into your original equation - what does it lead to?
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@Obumpa have you tried putting y=x into your original equation?
yes 0=45 I get it now thanks
yw :)
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