Simplify 4th root of 400/ 4th root of 5
Please explain ur answer cause I keep gettin it wrong
\[\frac{\sqrt[4]{100}}{\sqrt[4]{5}}\]?
@kimmii23 ???
yess but its 400 instead of 100
\[\sqrt[a]{b}=b^{\frac{1}{a}}\\and\\\frac{a^b}{c^b}=(\frac{a}{c})^b\] so \[\frac{\sqrt[4]{400}}{\sqrt[4]{5}}=(\frac{400}{5})^{\frac{1}{4}}=(80)^{\frac{1}{4}}=\sqrt[4]{80}=\sqrt[4]{16*5}=\sqrt[4]{16}\sqrt[4]{5}=2\sqrt[4]{5}\]
\[\sqrt[a]{b*c}=\sqrt[4]{b}*\sqrt[a]{c}\]
ssrock showed how you can simplify the problem to 4th root of 80 to find the 4th root of 80, factor 80 into its prime factors: 2*40 = 2* 2*20= 2*2*2*10= 2*2*2*2*5 and look for "groups of 4" (because you are doing 4th root) there is only one group of four 2's. you can take out the 4 twos, and replace them with 1 two on the outside. the 5 stays inside you get \[ 2\sqrt[4]{5}\]
OHHHH! I got stuck at the 80 that was my issue..didnt break that down thanks
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