is y = log2x a logarithmic function?
anyone?
\[y = \log _{2}x\]
is that a logarithmic function, hmmm let's see \(\bf is\ y = \color{red}{log}_2x \qquad \text{ a }\color{red}{\text{log}}\text{arithmic function?}\) what do you think?
yes well it doesn't look like most of the logarithmic functions i've dealt with in the lesson so i didn't know if they were trying to confuse me. guess not.
so how do you evaluate log10 ?
depends on the base, usually a calculator :)
what do you mean depends on the base? the question is simply: Evaluate log10.
i did it on a calculator and it came out as 1
if you had a 0 on the calculator, yes, is 1
but that would be \(\large log_{10}0\)
how do you write this as a logarithmic function? \[y = 2^{x}\]
you keep sending me a graphic...
yes, it's nice isnt' it :)
...
the graphic show the relationship of the logarithmic notation to the exponential notation
the first two times i clicked that graphic it was just a purplemath advertisement graphic. the third time i clicked on it it actually did what you were talking about.
so, how would you write \(y = 2^x\) as an exponential notation?
as logarithmic notation rather
log2y = x
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