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Mathematics 12 Online
OpenStudy (anonymous):

Find the inverse of the function: f(x) = 6x^2 + 2x + 5

OpenStudy (anonymous):

Wait a sec

OpenStudy (anonymous):

K this questions a bit weird is it a part of another question? Cause in functions you cant have a parabolic equ.

OpenStudy (anonymous):

a what?

OpenStudy (anonymous):

oh I see

OpenStudy (anonymous):

I just did a whole assignment that took me 4 hours with the notion that this was a function. This was my last question on it. -.-

OpenStudy (anonymous):

But if its a basic functions i guess you could still do it

OpenStudy (anonymous):

so it still works as a function?

OpenStudy (anonymous):

Wait a sec let me work something out

OpenStudy (anonymous):

when x=7 then f(7)=313 so doesnt that make it a function?

OpenStudy (anonymous):

So we have x values

OpenStudy (anonymous):

?

OpenStudy (anonymous):

So the problem here is that for every x value we put in the equ. We get a y value back

OpenStudy (anonymous):

But for every y value we put in the equ. We get 2 x values

OpenStudy (anonymous):

Have you ever heard of one to one function?

OpenStudy (anonymous):

Anyways goodluck I gtg

OpenStudy (anonymous):

yea but there can be two x values for one y

OpenStudy (anonymous):

\[y=6x^2+2x+5\rightarrow 6x^2+2x+5-y=0\]\[x=\frac{ -2+\sqrt{4-4·6·(5-y)} }{ 12}=\frac{ \sqrt{6y-29}-1 }{ 6 }\]

OpenStudy (anonymous):

I don't think that the function has inverse The idea is to complete the square then solve for x, the problem that u did not specify any interval , however , to make the inverse possible you should consider any interval includes only one complete half the parabola or some interval of it

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