Mathematics
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OpenStudy (anonymous):
Help!
Simplify:
1. (-z)^3(3z^4)
2. 5(x^2z^6)^3(5x^2z^6)^-3
Thank you!:)
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jimthompson5910 (jim_thompson5910):
what does (-z)^3 simplify to
OpenStudy (anonymous):
-z?
I don't know... :/
jimthompson5910 (jim_thompson5910):
close
jimthompson5910 (jim_thompson5910):
(-z)^3 = (-1*z)^3
(-z)^3 = (-1)^3*(z)^3
(-z)^3 = -1*z^3
(-z)^3 = -z^3
jimthompson5910 (jim_thompson5910):
(-z)^3(3z^4)
turns into
-z^3*3z^4
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jimthompson5910 (jim_thompson5910):
what's next?
OpenStudy (anonymous):
add the z's but the negative is still messing me up :/
jimthompson5910 (jim_thompson5910):
think of
-z^3*3z^4
as
-1z^3*3z^4
jimthompson5910 (jim_thompson5910):
so the coefficients are -1 and 3, they multiply to -1*3 = -3
jimthompson5910 (jim_thompson5910):
z^3 times z^4 = z^(3+4) = z^7
so the final answer is -3z^7
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OpenStudy (anonymous):
thank you! :)
can you help me with the second one as well?
jimthompson5910 (jim_thompson5910):
how far did you get with it?
OpenStudy (anonymous):
does exponents distribute first?
if so, does the ^3 distribute to the 5 as well or just the (x^2z^6)?
jimthompson5910 (jim_thompson5910):
the exponent of 3 only applies to terms inside the parenthesis
jimthompson5910 (jim_thompson5910):
so (x^2z^6)^3 means you cube x^2 and z^6
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OpenStudy (anonymous):
I got 1/25 after simplifying
jimthompson5910 (jim_thompson5910):
let me check
jimthompson5910 (jim_thompson5910):
you are correct
OpenStudy (anonymous):
thank you for helping me! :) you're the best! :)
jimthompson5910 (jim_thompson5910):
you're welcome