Question

How many units apart are the points (4, -3) and (-4, 3)?

Answer 1

Can someone please explain?

Answer 2

Use the distance formula to find the distance between two points:

\[d=\sqrt{(X_{1}-X_{2})^{2}+(Y_{1}-Y_{2})^{2}}\]
Just plug in your point coordinates and simplify.

Answer 3

so 4-(-4) ^+ (-3)-3^ ????????? then do the square root of what I get?

Answer 4

You need to square each of those differences (I think that's what you mean, but it's hard to tell with just text).

Answer 5

Tell me what you get, and I'll tell you if it's right. :)

Answer 6

Would it be 64+9=73 then I square root 73?

Answer 7

Check that 9.

Answer 8

\((-3-3)^2=?\)

Answer 9

um...0 ?

Answer 10

What's -3-3?

Answer 11

-3 - 3 = -6

Answer 12

so 58 ?

Answer 13

Good. now square that...?

And add to 64

Answer 14

No, look at the equation again. You squared the difference of x's but are forgetting to square the difference of the y's. :)

Answer 15

oh so that means I have to square 64 then too right?

Answer 16

No, the 64 is already the square!

Answer 17

OH I GET WHAT U MEAN

Answer 18

I was getting confused with the square root ,and squared

Answer 19

Just take it one step at at time. :)

Answer 20

3364 ?

Answer 21

Oh lord. how did you get that? lol

Answer 22

58x58 i dunno!

Answer 23

what do I do!!?!?

Answer 24

sorry, i'm having technical issues.... hang on.

Answer 25

Oh okay (:

Answer 26

\[d=\sqrt{(-4-4)^{2}+(3-(-3))^2}\]
\[=\sqrt{(-8)^{2}+(6)^2}\]

You basically got this far (notice I changed the order, just to be consistent with the formula in terms of calling the the point "1" and the other point "2"... but the order you subtract the coordinates in won't really matter, since it only changes the sign and we are going to square the result).

Answer 27

NOW do the squares FIRST - they are under the square root - so you need

\[(-8)^{2} ~~\text{and}~~~ 6^2\]

Answer 28

-64 ? and 36?

Answer 29

No real number, squared, is negative

Answer 30

(but the 36 is correct)

Answer 31

so its just left as 64 and 36

Answer 32

remember, it's \((-8)^2\), NOT \(-8^2\), there is an important difference!

Answer 33

Well, yes, it's "left" as those because that's what they ARE! :) OK, so now you have:

\[\Large =\sqrt{64+36}\]

Do the sum. THEN take the root.

Answer 34

64+36=100 then rooted=10

Answer 35

Tah-dah! :)

Answer 36

So thats my answer? 10 Units away?

Answer 37

yeppers, that's what the distance formula tells you. :)

Answer 38

wow thanks (: explained very well...I dunno how to give you more than 1 medal id give you like 5 or something if I could

Answer 39

Haha, thanks, one is fine. :) Happy to have helped, good job sticking with it and working through the explanation! :)