Question

How do I do the Pythagorean Theorem for this?

13 square root 5 + b^2 = 13^2

Answer 1

why do you want to use the Pythagorean Theorem?

Answer 2

Trig Function.

Answer 3

? okay… and?

Answer 4

It says find sec θ if sin θ = 3 square root 13 / 13

Answer 5

I need to label the triangle of the missing adjacent side.

Answer 6

do it.

Answer 7

I don't know how to do a^2 with the 3 square root 13..

Answer 8

you don't know what?

Answer 9

you mean cube root?

Answer 10

\[3\sqrt{13}\]

Answer 11

that means
\[\sqrt{13\times9}\]

Answer 12

\[\sqrt{117}\]

Answer 13

k what do you do next?

Answer 14

are you trying to solve b in
13 square root 5 + b^2 = 13^2 ?

Answer 15

So \[\sqrt{117}+ b^2 = 169\]

Answer 16

How do I continue off of that?

Answer 17

you might want to isolate b^2 by deducting the whole sqrt(117) on both sides

Answer 18

Would it just be 169 - \[\sqrt{117}\] on the c side?

Answer 19

I don't think your equation was written out properly, but we'll see

Answer 20

Pfft, you don't need me, you got the great Nin here

Answer 21

Sorry I thought he wasn't reading anymore!

Answer 22

what c side?
now try to get rid of the exponent 2 by obtaining the square root of b^2 and also of the other side of the equation

Answer 23

\[b^2 = 169 - \sqrt{117}\]

Answer 24

Is what I'm understanding.

Answer 25

just about right

Answer 26

if you want to solve for b, you isolate it to one side

Answer 27

It is isolated.

Answer 28

we accomplished that

Answer 29

but you have b^2 still
a square root of b^2 is b so try to square root both sides of the equation

Answer 30

b = \[\sqrt{169-\sqrt{117}}\]

Answer 31

ya
square root of 169 is?

Answer 32

13.

Answer 33

great! now square root of a square root means?

Answer 34

I'm not sure..

Answer 35

it's the same as exponents, you multiply the radical

Answer 36

So how does that look?