Question

domain of 4/sqrt(x+3)

Answer 1

Hello @asdf1234asdf Welcome to openstudy :)
To find the domain, first set that x+3 equal to 0

Answer 2

@Luigi0210 so 4sqrt3/3?

Answer 3

solve
\[x+3>0\] for \(x\) in exactly one step

Answer 4

you can't take the square root of a negative number
you can't divide by zero
therefor \(x+3\) must be greater than 0

Answer 5

@satellite73 so the 4 has nothing to do with finding the domain?

Answer 6

nope

Answer 7

would be the same if you have
\[\frac{7}{\sqrt{x+3}}\] or
\[\frac{\pi}{\sqrt{x+3}}\]

Answer 8

@satellite73 would i use x+3>0 for interval notation? or would i need greater than or equal to?

Answer 9

you would solve \(x+3>0\) for \(x\)