Question

Show that e^x grows faster than e^cos(x).

Answer 1

Show that \(\dfrac{d}{dx}e^x>\dfrac{d}{dx}e^{\cos x}\).

Answer 2

You'll probably have to use the fact that \(\cos x\) and \(\sin x\) are bounded by \(\pm1\).

Answer 3

Sorry, I don't understand what you wrote.

Answer 4

Show that the derivative (rate of change) of e^x is greater than the derivative of e^(cos x).

Answer 5

Latex problems again?

Answer 6

Do you have to take the limit?

Answer 7

Yes, I think the question will have you consider the end behavior of e^x and -sinx e^(cosx).