Question

f(x)= (37−2x)^1/2
find the domain of the given function

Answer 1

\(f(x)=\sqrt{37-2x}\) Is that it?

Answer 2

Like is that the function?

Answer 3

yes

Answer 4

pls also tell how did you arrive at the answer.

Answer 5

Ok. So then we know that \(\sqrt{0}=0\). But the "thing" inside the square root cannot be negative. So we have:
\[(37-2x) \geq 0\]
\[37 \geq 2x\]
\[\frac{37}{2} \geq x\]

Therefore, the domain is:

\[D=\Big[{x \in R} \phantom{.} \Big| \frac{37}{2} \geq x\Big]\]

Answer 6

hmm... lemme plug this answer in my homework. I have tried this question 5 times, hadn't got it right so far. Hope it works this time.

Answer 7

I hope so too!

Answer 8

Nope it says the answer is wrong.

Answer 9

I had to write it in interval format so I wrote it as [37/2,infinity)

Answer 10

Oh I see yeah that's another way of writing it:
\[D=\left[{x \in R} \phantom{.} \Big| x \in \left(-\infty,\frac{37}{2}\right]\right]\]

Answer 11

I see i was writing it wrong. thanks dude.

Answer 12

Anytime man