A high-altitude spherical weather balloon expands as it rises due to the drop in atmospheric pressure. Suppose that the radius r increases at the rate of 0.16 inches per second and that r = 38 inches at time t = 0. Determine the equation that models the volume V of the balloon at time t and find the volume when t = 280 seconds.
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OpenStudy (nincompoop):
you also have to understand that the temperature is another variable to consider.
OpenStudy (anonymous):
r(t)=0.16*t+38
V=(4/3)(pi)(r(t))^3
That is where I am going...
OpenStudy (anonymous):
V(t) = (0.16t +38)^3 * 4/3 * pi
OpenStudy (anonymous):
Volume as a function of time: V(t)
OpenStudy (anonymous):
This is my final answer:
|dw:1377661794615:dw|
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OpenStudy (anonymous):
What is 2,377,823,51 in^3?
OpenStudy (anonymous):
t = 280 yes, your answer is correct
OpenStudy (anonymous):
that is a huge balloon
OpenStudy (anonymous):
I know, laughing out loud ! Thank for your help :)
OpenStudy (anonymous):
I meant thank You
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