Integrate 5*csc^4x*cot^6x*dx

Question

luigi0210 · Answer

Hello @meggie94 Welcome to Openstudy :)

anonymous · Answer

Cheating is not permitted...

anonymous · Answer

Cheating is against terms and services, if you took the time to read it...

luigi0210 · Answer

@shaagasda Yes, cheating on tests, exams, etc is not permitted

anonymous · Answer

Tell that to him...

luigi0210 · Answer

What makes you think he's cheating?

anonymous · Answer

That question was in a math packet I recently did.

anonymous · Answer

I'm not trying to cheat, I just really don't know what to do...

luigi0210 · Answer

If it's in a packet or worksheet that's fine.

anonymous · Answer

Lol...

anonymous · Answer

That's still illegitimate if he doesn't learn... People just spit answers out like it's water.

luigi0210 · Answer

Besides, there could be millions of different questions out there on tests that cold be on packets and visa versa

anonymous · Answer

yuck fou

anonymous · Answer

btich

anonymous · Answer

sh is hee to ask a question ..... hey meggie write ur question in proper way thro eqation i can help u then

anonymous · Answer

$$I=\int\limits\limits_{}^{}\cot^6(x)*(\cot^2(x)+1)\csc^2(x) \rightarrow \int\limits\limits_{}^{}\cot^8(x)\csc^2(x)+\cot^6(x)\csc^2(x)$$
 now you can assume u=cot(x) and you will directly find that the integral equals to: 
$$\frac{ -\cot^9(x) }{ 9 }-\frac{ \cot^7(x) }{ 7 }$$