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integrate[sqrtx/(x-4)
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\[\Large \int \frac{\sqrt x}{x-4}dx\]
use substitistion man
He has already left...
i knw i just doing when he comes may take his answer
u will have (X^1/2)^2-2^2 and this is how u r goona substitue x^1/2=t and then t/t^2-2^2 nw using substitution u can solve it
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also u hv to change dx to dt remember it ok
use x=t^2 dx =2tdt the given question becomes 2t^2/(t^2-4)=2*(t^2-4 +4)/(t^2-4)=2* (1 + 4/(t^2-4)) which can be integrated easily
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