Question

Consider the quadratic equation ax^2+bx+c. Suppose that b and c can only take the values [1,2,3,4,5,6]. For which values of b and c does the equation have real roots?

Answer 1

do I have to use the quadratic formula on each combination ?

Answer 2

alright..but do I have to plug in the values to the discriminant?

Answer 3

Whether or not it has real roots also depends on the value of a, right?
I mean, if a is negative, then it doesn't really matter what b and c are, the quadratic expression WILL have real roots...

Answer 4

ummm how did you get b= c/2?

Answer 5

look at the discriminant b^2-4ac putting the values of abc u can take ur answer

Answer 6

ok if we let b=2 and c = 1
b^2-4ac
2^2-4(1)(1) = 4-4 =0

Answer 7

here we have to consider a too

Answer 8

but a is like one on default since b and c is 1-6

Answer 9

Are you absolutely sure that a = 1?
Because it doesn't say so... I'm not really a fan of assumptions ^_^

Answer 10

so it has to be something...like a b c values that can produce something greater than 0?

Answer 11

hey poeple a= not equal to one ... for real roots b2-4ac=0 frrom here putting b c we can find a.