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Mathematics 7 Online
OpenStudy (anonymous):

Find all solutions in the interval [0, 2π). sin2 x + sin x = 0

OpenStudy (psymon):

We cannot have different angles when we solve for these. We have a 2x and an x, and we have to have them be the same. So what we want to do is use an identity on sin2x so we can get functions with only an angle of x. Do you know the double-angle formula for sin2x?

OpenStudy (luigi0210):

Is that: \[\sin^2x\] Or \[\sin2x\]

OpenStudy (psymon):

Yeah, completely different if thats supposed to be squared xD Which I kinda think it is.

OpenStudy (anonymous):

yes, it is squared.

OpenStudy (luigi0210):

If it's squared then it's simple simple simple

OpenStudy (psymon):

Alrighty. Then this we would factor in the same way we would as if those sin(x)'s were just regular x's. We factor it just like we woudl this: \[x ^{2}+x=0 \]

OpenStudy (psymon):

So if you know how to factor the above quadratic, then you can factor this sin^2x + sinx = 0 equation :3

OpenStudy (anonymous):

2 sin(x/2) cos(x/2) (sin(x/2)+cos(x/2))^2 = 0

OpenStudy (psymon):

Why did we do that? All we need to do is factor it like a quadratic. Its done in the same fashion as something like this: \[x ^{3}+x=x(x ^{2}+1)\] Youd be doing that process with your equation :3

OpenStudy (anonymous):

Oh. I tend to over think things...

OpenStudy (psymon):

Well, youre just not used to seeing a quadratic being with trig functions xD

OpenStudy (anonymous):

Exactly.

OpenStudy (psymon):

Thats why trig is tricky. Nothing like all the tons of algebra we have to do to get here :p SO following the method I did above, think you can factor what we have with our sines?

OpenStudy (akashdeepdeb):

Is this query cleared?

OpenStudy (psymon):

We're still working it xD

OpenStudy (akashdeepdeb):

Any 'help' needed?

OpenStudy (psymon):

I dont believe so. Just waiting for her to respond to see where we might need to go from here.

OpenStudy (akashdeepdeb):

xD

OpenStudy (anonymous):

I'm lost, I don't know what factor.

OpenStudy (anonymous):

to factor

OpenStudy (psymon):

Ah, okay. Well, akash is eager, lol.

OpenStudy (anonymous):

Hopefully, Akash can make this problem a bit less complicated like the previous one.

OpenStudy (psymon):

Yeah, you have a hard time understanding me it seems. Im sure hell do much better than what I can do.

OpenStudy (akashdeepdeb):

1 sec.

OpenStudy (anonymous):

No, it's just that these problems are really difficult for me. Don't take it personally.

OpenStudy (akashdeepdeb):

Guys chill out on that!! LOL

OpenStudy (psymon):

No, its not that I take it persoanlly, I just think I suck compared to everyone else. So usually once someone else joins in ont he problem I leave because Im just going to embarrass myself.

OpenStudy (akashdeepdeb):

All you have to do is take sin x(sin x + 1) = 0 Now either sin x = 0 Or sin x = -1 So x can be 0' or 270'

OpenStudy (anonymous):

Yeah, I really despise any type of conflict...

OpenStudy (akashdeepdeb):

'LoveIsKey' after all

OpenStudy (psymon):

Which is why its usually best for me to leave when others come in and join. I tend to cause a lot of conflict and drama.

OpenStudy (anonymous):

@Psymon You should not think like that. This is not the first time you have aided me in a math problem, you're amazing. Do not underestimate yourself !

OpenStudy (akashdeepdeb):

PS. Psymon you have a score of 74 now! PROOF THAT YOU DON'T SUCK!! :D

OpenStudy (psymon):

that means nothing, lol. It means I go to a lot of problems xD

OpenStudy (akashdeepdeb):

LoL, No chill out on the 'Insulting yourself' XD :D It is FUNNY

OpenStudy (akashdeepdeb):

Okay, Not drifting away from the topic @Loveiskey18 Did you understand what I did?

OpenStudy (psymon):

Lol, it what I always do xD

OpenStudy (anonymous):

How did you get 270?

OpenStudy (akashdeepdeb):

sin 270 is -1 That's how! :)

OpenStudy (anonymous):

I'm just going to agree with you... -__-

OpenStudy (psymon):

Sin refers to y-coordinates. If you actually look at the circle and point our where 270 is.... |dw:1377670372265:dw|

OpenStudy (akashdeepdeb):

Why why why??? Ask me if you have any question!!!!

OpenStudy (akashdeepdeb):

Yeah! Psymon is right over there!

OpenStudy (anonymous):

This sin, cos, tan stuff is the reason why I can not get an amazing score on my ACT . Why do we have them, because I am really going to use sin, cos and tan in my daily life.. :)

OpenStudy (psymon):

Well, a lot of people think math is a sin.

OpenStudy (akashdeepdeb):

Try Learning all cosine, sine and tangent values for 0, pi/2 , pi , 3pi/2 , 2pi radians! It WILL help!! :D

OpenStudy (psymon):

And the people who love math say without geometry life is pointless.

OpenStudy (anonymous):

Oh, the unit of Circle !

OpenStudy (akashdeepdeb):

Lol There!!

OpenStudy (akashdeepdeb):

@Loveiskey18 Did you get how I computed this though?

OpenStudy (psymon):

Yep yep. Absolutely. All the values on the unit circle refer to actual points on a graph. Sin(pi/6) is 1/2 because the y-coordinate, if you were to plot it, is 1/2!

OpenStudy (anonymous):

Yes, somewhat. Laughing out loud

OpenStudy (akashdeepdeb):

What is the other 'Somewhat' you do not get?

OpenStudy (anonymous):

Oh, I'm just wondering how we are going to get from 270 to this: x = 0, π, pi divided by three, five pi divided by three x = 0, π, pi divided by three, two pi divided by three x = 0, π, four pi divided by three, five pi divided by three x = 0, π, three pi divided by two. That is the somewhat that I do not get.

OpenStudy (akashdeepdeb):

Btw I forgot to mention even 180 degrees would be a value because sin 180 or sin pi is 0 :D So it should be Option D.!!! :D

OpenStudy (psymon):

Makes me think of the little cartoons in my math book: |dw:1377670698620:dw|

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