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antidifferentiate 3x-1/x+1 please help
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sub u = x+1 du = dx
\[\int\limits \frac{3(u-1) -1}{u} du = \int\limits \frac{3u-4}{u} du = \int\limits 3 du - 4\int\limits \frac{1}{u} du\]
Why not simplify first?
Thanks that really helps.
\[\frac{3x - 1}{x+1} = \frac{3x + 3 - 4}{x+1} = \frac{3x + 3}{x + 1} - \frac{4}{x + 1} = 3 - \frac{4}{x + 1}\]
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Now anti-differentiate \[\int\left(3 - \frac{4}{x + 1}\right)dx\]
You can do that to avoid u-sub
I actually like this way better. Its easier to work out this way.
Which way?
I made it look more complicated than it really is
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I was just showing all the steps
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