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You invest $350 in an account with an interest rate of 1.2% compounded continuously. How much money would be in the account after 10 years? Round your answer to the nearest whole number.
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i know the formula is A = Pe^rt but i don't seem to be getting the right answer.
\[A = 350(e)^{.012}(^{10})\]
@phi
the 10 should be multiplying the 0.012 you should get this \[ A = 350 e^{0.12}\] what do you get for a number ?
394.623898053
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that looks good.
rounded to the nearest whole number so 395. okay. thank you.
If you did compounded yearly, so the yearly interest rate is 0.012 the formula is 350* 1.012^10 which gives 394.34, very close to compounding continuously I did that as a quick check.
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