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Mathematics 8 Online
OpenStudy (katherinesmith):

graphing question; please help!

OpenStudy (katherinesmith):

1) The red graph (1) is the graph of f(x) = 2x. Describe the transformation of the blue function (2) and write the equation of the graph.

OpenStudy (anonymous):

dont listen to wwesuperstar

OpenStudy (katherinesmith):

well can someone help me..

OpenStudy (anonymous):

it's -2x

OpenStudy (katherinesmith):

i have to describe the transformation and write the equation of the graph.

OpenStudy (anonymous):

the same x value goes to negative y value so you just should take the negative of function

OpenStudy (katherinesmith):

that does not help me describe the transformation... and i don't even know if that equation makes sense.

OpenStudy (katherinesmith):

maybe @jim_thompson5910 can help me

OpenStudy (phi):

The equation is 2^x it looks like they shifted it left by 1, flipped it (multiply by -1) and then shifted up by 3

OpenStudy (katherinesmith):

but the equation of the first graph is 2^x, so how can it be the same for the second graph?

OpenStudy (phi):

the original is 2^x

OpenStudy (phi):

do you know how to shift a graph to the left by 1 ? you replace x with x+1

OpenStudy (katherinesmith):

the red graph is the graph of 2^x. so the equation of both graphs is 2^x?

OpenStudy (jdoe0001):

he's not saying that, he's saying, use 2^x and apply the transformations as explained

OpenStudy (phi):

the red graph is 2^x the blue graph is the red graph shifted left by 1, reflected about the x-axis (multiply by -1) and then shifted up by 3

OpenStudy (katherinesmith):

so 2x - 1(-1) + 3?

OpenStudy (phi):

can you type that in with ^ and parens to show what is where ?

OpenStudy (katherinesmith):

i have no idea how to write it.

OpenStudy (katherinesmith):

i'm fiddling with it and i can't figure it out.

OpenStudy (phi):

you start with 2^x or 2^(x) which is \( 2^x\) shift to the left 1 step means replace x with (x+1) can you replace x with (x+1) ?

OpenStudy (jdoe0001):

use the whiteboard maybe

OpenStudy (katherinesmith):

\[2^{x + 1}\]

OpenStudy (phi):

now reflect about the x-axis you now have y= 2^(x+1) reflecting about the x-axis is done by multiplying by -1 (this makes the red curve go negative instead of positive) can you multiply -1 times 2^(x+1) ?

OpenStudy (katherinesmith):

is it \[y = -2^{x + 1}\]

OpenStudy (phi):

you write \[ -1 \cdot 2^{x+1} \] or just \[ -2^{x+1} \]

OpenStudy (katherinesmith):

okay i got that

OpenStudy (phi):

finally they shifted up by 3. whatever y value we get from \[ y = -2^{x+1} \] is low by 3 units. add 3 to shift up.

OpenStudy (katherinesmith):

\[y = -2^{x + 1} + 3 \]

OpenStudy (phi):

yes, that is the answer. as a check, when x= -1 , the blue curve is - 2^0 + 3 = -1 + 3 = 2 when x =0, the blue curve is -2^1 + 3 = -2+3 = 1 and when x =2, the blue curve is -2^3 + 3 = -8+3 = -5 you can check that the blue curve goes through the points (-1,2), (0,1) and (2,-5)

OpenStudy (katherinesmith):

this actually makes me want to shoot myself because i have like 5 more of these.

OpenStudy (phi):

Does that mean you don't understand what is going on ?

OpenStudy (katherinesmith):

i understand the equation... somewhat. i don't really understand the transformations. like okay this is the next one: The red graph (1) is the graph of f(x) = 2x. Describe the transformation of the blue function (2) and write the equation of the graph.

OpenStudy (phi):

you should use the ^ because 2x means 2*x which is different.

OpenStudy (katherinesmith):

i didn't notice i forgot. normally i'm good with that

OpenStudy (phi):

Just looking at the picture, without going into details, how do you get to the blue curve. It looks like it was shifted to the right, and shifted down.

OpenStudy (katherinesmith):

okay, i see that. but how do you know how many units right and down it was shifted

OpenStudy (phi):

look at the flat part of the curve (on the left). how far down do you count to get from the red to the blue curve? that will be the shift down (it will be a negative number)

OpenStudy (katherinesmith):

-6?

OpenStudy (phi):

so that will be your y shift now for the x shift. look at the red curve. it is near zero on the left and then goes up. see where it goes up exactly 1 step ? that happens at x=0 now do the same for the blue curve. at what x does the blue curve go up exactly 1 step ?

OpenStudy (katherinesmith):

-5

OpenStudy (phi):

that is the y value. what is the x value ?

OpenStudy (katherinesmith):

4

OpenStudy (phi):

yes. the shift is 4 to the right. that means you replace x with (x-4) (going left/right is confusing.... to shift right 4 steps, you add -4 to the x) can you come up with the new equation, starting with y = 2^x and shifting right 4 steps, and down 6 steps ?

OpenStudy (katherinesmith):

sike it's 5

OpenStudy (katherinesmith):

wait no. it is 4. okay let me try

OpenStudy (katherinesmith):

\[y = 2^{x - 4} - 6\]

OpenStudy (phi):

now do a check. when x=6 what do you get for y with your equation ?

OpenStudy (katherinesmith):

-2

OpenStudy (phi):

does the blue curve go through the point (6,-2) ?

OpenStudy (katherinesmith):

yes

OpenStudy (phi):

so that looks good.

OpenStudy (katherinesmith):

thank god. 4 more. kill me

OpenStudy (phi):

you should make it a new post.

OpenStudy (katherinesmith):

okay i am.

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