Given that f(x) = x2 − 3x + 3 and g(x) = the quantity of x minus one, over four, solve for f(g(x)) when x = 5
How would I solve this problem?

Question

Given that f(x) = x2 − 3x + 3 and g(x) = the quantity of x minus one, over four, solve for f(g(x)) when x = 5
How would I solve this problem?

zepdrix · Answer

$$\Large \color{royalblue}{\text{Welcome To OpenStudy! :)}}$$

zepdrix · Answer

$$\Large f(x)=x^2-3x+3 \qquad\qquad g(x)=\frac{x-1}{4}$$

$$\Large g(\color{royalblue}{5})=\frac{\color{royalblue}{5}-1}{4} \qquad\to\qquad \color{#CC0033}{g(5)=1}$$


$$\Large f\left(\color{#CC0033}{g(5)}\right) = f(\color{#CC0033}{1})$$

zepdrix · Answer

$$\Large f(\color{#F35633}{x})=\color{#F35633}{x}^2-3\color{#F35633}{x}+3$$Understand how to find f(1) from here?$$\Large f(\color{#F35633}{1})=?$$

anonymous · Answer

I don't really follow.

zepdrix · Answer

Hmm function notation can be a little tricky.
Maybe there is another way to explain it. hmmmm

anonymous · Answer

I just really need an answer to make me understand. I've been relearning the function thing since last week and I'm having I problem learning it online.