Question

log5x = 3

Answer 1

\[\log _{5}x = 3\]

Answer 2

You could start by converting it to an exponent equation

Answer 3

notice the 5 is a subscript

Answer 4

Yes, I see that.
You can still convert it.

Answer 5

okay, how.

Answer 6

make each side the exponent of 5

Answer 7

making the log_5 the exponent of the base (5 here) "undoes" the log

\[ b^{\log_b(a)} = a \]

Answer 8

can you plug the numbers into the start of the equation?

Answer 9

you start with
\[ \log _{5}x = 3 \]
make each side the exponent of the base = 5
\[ 5^{\log _{5}x} = 5^3\]

Answer 10

okay...

Answer 11

the ugly expression on the left side is just x (which is why we did it)

Answer 12

x = 25?

Answer 13

x= 5^3 = 5*5*5= 125

Answer 14

that 3 looks like a 2 because of how small the font is

Answer 15

logarithms make me want to die slowly

Answer 16

logs are confusing. but logs and exponents of a base go together.

Answer 17

\[\log _{2} (x - 3) = 5\]

Answer 18

same idea, different base

Answer 19

same formula?

Answer 20

\[ b^{\log_b(a)} = a \]

Answer 21

\[2^{\log2(x - 3)} = 2^{5}\]

Answer 22

is that right so far

Answer 23

as long as the big 2 is really a little 2 in the lower right.

Answer 24

the big two in the front or the end?

Answer 25

the log_2 should give you a 2 in the lower right

Answer 26

\[ 2^{\log_2(x - 3)} = 2^{5} \]

Answer 27

okay so then you have x(x-3) = 2^5 correct?

Answer 28

just
(x-3) = 2^5

Answer 29

x = 35

Answer 30

this may be confusing, but it should be easy to remember

\[ \cancel{2}^{\cancel{\log_2} x} = x \]

Answer 31

\[3\log _{6} (x + 1) = 9\]

Answer 32

is my next one

Answer 33

divide both sides by 3
then you have the same problem, with a different base

Answer 34

\[\log _{6}(x + 1) = 3\]

Answer 35

i got x = 215

Answer 36

yes

Answer 37

woohooo! i will open a new question