Question

Find the average rate of change of f(x)=1+sin x over interval [0,pi]

Answer 1

Average rate of change of a function \(f\) over some interval \([a,b]\), provided that \(f\) is continuous over the interval, is
\[\frac{f(b)-f(a)}{b-a}\]

Answer 2

you got this?

Answer 3

@SithsAndGiggles Same thing came to my head but what is a? it is 0?

Answer 4

Yes, \([a,b]=[0,\pi]\), so \(a=0\) and \(b=\pi\).

Answer 5

OK. Now I'm calm. Oh you forgot to add the limit as b approaches a.

Answer 6

That's the case for instantaneous rate of change. We just want the average rate of change.

Answer 7

Oh lol I didn't read the question well.