Question

solve 2sinxcosx=0
sin2x=0
2x=sin^-1 (0)
Is the soln. x=pi/n or x=pi n/2?

Answer 1

oh, there's a typo... x=pi n or x=pi n /2

Answer 2

You an do it without alteration.

sin(x) = 0 at x = 0 and pi
cos(x) = 0 at x = pi/2 and 3pi/2

Or, you can use the transformation you selected.

sin(2x) = 0 at 2x = 0, pi, 2pi, 3pi giving x = 0, pi/2, pi, 3pi/2

Isn't it interesting that mathematics works?!

Answer 3

so... you're saying that the latter, x=pi n /2 is the correct answer?

Answer 4

\[0,\frac{\pi}{2},\pi,\frac{3\pi}{2},2\pi,...\] any place where either sine is zero or cosine is zero

Answer 5

if you want to abbreviate this you can write
\[x=\frac{n\pi}{2},n\in \mathbb{Z}\]

Answer 6

oh... now I see what you were trying to tell me. hahaha but representing it would be pi n /2, correct?

Answer 7

oh, ok thank you so much!
my firend gave me a wrong answer LOL

Answer 8

don't trust friends

Answer 9

:) hahaha ok i wont

Answer 10

lesson learned? :)

Answer 11

u r one of my favorite ppl on here~ hahaha keep at it!