i need serious help with trigonometric values in the four quadrants of a circle.
i have read my lesson over again 2 times and still can not figure out the process to solving something like this: what is the exact value of sin \[\frac{ \pi }{ 2}\] as found on the unit circle?
sin goes in front of the fraction
any idea @zepdrix ?
Ok let's start really basic first. Do you know your orientation within the unit circle? Like do you know where an angle of \(\large \theta=0\) starts? And do you know which way to rotate and how far to go to get to \(\large \pi/2\) ?
i know pi/2 is equivalent to 90 degrees
ok good.
|dw:1377747637549:dw|
|dw:1377747711955:dw|Before we figure this problem out ~ I just wanna make 2 really quick notes that I think might help. Let's start with some arbitrary angle like this.
|dw:1377747788638:dw|There are a couple ways to get to this point on the unit circle. By spinning theta radians around the circle OR by moving a distance in the x direction, and a distance in the y direction.
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