Ask your own question, for FREE!
Chemistry 15 Online
OpenStudy (anonymous):

The first four ionization energies for element X (not in kJ/mol) are 170, 350, 1800, 2500. The first four ionization energies for element Y are 200, 400, 3500, 5000. Identify elements X and Y. (There may be more than one correct answer) Am I right if I say element X may be Magnesium and element Y may be Calcium?

OpenStudy (anonymous):

well the IE jumps at the removal of a valence electron after the ion is stable and both of these jump at the removal of their 3rd electron meaning that have to be in group 2

OpenStudy (anonymous):

would that be correct?

OpenStudy (chmvijay):

yaa that is correct why mg ? why not sr ?

OpenStudy (anonymous):

because Mg has less shielding and Sr would have a larger I1

OpenStudy (abb0t):

You know, I just took inorganic II last Winter and we kind of went over this stuff and I forgot all of this. Funny, huh?

OpenStudy (anonymous):

I would say yes but I need help so it's kinda not funny :)

OpenStudy (abb0t):

Ok, well Sr would have a larger l1? What does that mean?

OpenStudy (anonymous):

wait no it would have a smaller \(\text{I}_1\) -- more shielding, less energy

OpenStudy (chmvijay):

thats right

OpenStudy (anonymous):

Sr isnt what I'm asking though...would it be correct to say element X may be Mg and element Y may be Ca? @abb0t

OpenStudy (abb0t):

If I remember correctly, yes. Shielding increases as you move down the periodic table, due to atomic size.

OpenStudy (anonymous):

so I'm right?

OpenStudy (abb0t):

Yeah, anything that has 2 valence \(e^-\) I would say is correct.

OpenStudy (anonymous):

alright, thanks guys! :)

OpenStudy (abb0t):

Sr would be a valid answer too. but then your x, would not be Mg, based on the given info. It would be Ca\(^{2+}\)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!