Question

ikykt

Answer 1

that is the second time i have seen this ridiculous question
where does it come from?

Answer 2

actually the last time i saw it there was another part about composing functions
in any case, here is my example
\[f(x)=5x+3\] that has two operations: multiplication and addition
i am sure you can make up your own

Answer 3

if you want to be fancy you can make a more complicated one, like
\[g(x)=x^2+5x+3\] or even
\[h(x)=\frac{x-1}{x+2}\] but no one likes fractions

Answer 4

if you plug one number in, you get one number out
for example for
\[f(x)=5x+3\] if you plug in 4 for \(x\) you get
\[f(4)=5\times 4+3=20+3=23\] and no other number

Answer 5

i am not really sure of what else you can say
plug a number in, get a number out

Answer 6

i am willing to bet, that since i just went through the steps of computing
\(f(4)\) that you can now do the analogous computation for \(f(3)\) right?

Answer 7

ok that is all you are being asked
if you want help with the "english' part i would say
take your number, which in this case is 3
multiply it by 5, in this example you get 15,
then add 3, which makes 18

that is what you got, right?

Answer 8

ah good thing we picked an easy one:
\[f(x)=5x+3\]

Answer 9

this function says "multiply by 5, add 3"
the inverse will say "subtract 3, divide by 5"
inverse operations in reverse order
so it will be
\[f^{-1}(x)=\frac{x-3}{5}\] HOWEVER

Answer 10

if you write exactly what i wrote, your teacher will think you cheated (even though it is correct)
so instead maybe write
" write \(y=5x+3\) then change \(x\) and \(y\) to get \(x=5y+3\) and solve the equation for \(y\) "
\[x=5y+3\\x-3=5y\\\frac{x-3}{5}=y\] and \(y\) is the inverse "