Question

What is the GCF in this expression?

3y²(y - 2) + 5(y - 2)

Answer 1

Any ideas?

Answer 2

@Avon ???

Answer 3

you can easily see which is G.C.F

Answer 4

What happens if you multiply it out?

Answer 5

OpenStudy values the Learning process - not the ‘Give you an answer’ process
Don’t post only answers - guide the asker to a solution.

Answer 6

$$\huge \text{No effort = No answer}$$

Answer 7

@Avon Well, are you ready to learn?

Answer 8

yea @skullpatrol

Answer 9

What happens if you multiply it out?

Answer 10

@skullpatrol the site is acting crazy thts y i could answer, but 3y^3+5y^2 is tht right

Answer 11

Yes, there is no common factor if you multiply it out.

Answer 12

@surjithayer please don't give away the answer

Answer 13

@skullpatrol so is 3 and 5 the GCF 3*1 AND 5*1 or is it 3y^2 =5 and that may equal 8y^2 do the y-2 cancel out

Answer 14

$$\huge 3y²(y - 2) + 5(y - 2)$$

Answer 15

3y+5y-2

Answer 16

What is that?

Answer 17

or is it 15=3*5

Answer 18

Do you know what a "common factor" is"

Answer 19

3+5=8

Answer 20

What is a "factor"?

Answer 21

3y²(y - 2) + 5(y - 2)=

3y^3-6y^2+5y-10=

1(3y^3-6y^2) + 1(5y-10)

Answer 22

im not good at this idk seriously

Answer 23

factor: When two or more numbers are multiplied each of the numbers is
a factor of the product.

Answer 24

ok i know that much @skullpatrol but what your not understanding is that im confused

Answer 25

You need to recall the distributive property: $$\huge ba+ca=(b+c)a$$ Remember?

Answer 26

$$\huge 3y²(y - 2) + 5(y - 2)=?$$