Electrostatics: You have a hollow sphere with a charge -2Q it has an inner radius R1 and outer radius R2 there is nothing inside the hollow cavity. Find the charge density at R1 and R2.
My instructor told us this in lecture. I have written: "We can argue that the charge density on the inner surface at R1 is =0. The reasoning is that E lines must originate from + and terminate at - charges. If it is minus charged in the inner space there needs to be a positive charge to originate from but E=0 so that cannot happen"
|dw:1377798974315:dw|
Is what I have drawn. I do not understand what he meant at all. I don't know if he meant that the -2Q was on the inside or if that was just a hypothetical and the -2Q is still residing elsewhere.
Charges will always lie only on the outer surface.. assuming its a conductor ofcourse.. and therefore.. what he is trying to say is that inside the conductor, charge must be zero and hence the charge density is also zero!
Could you explain that to me? I'm trying to reason through it. I'm stuck.
Is it because they would repel each other until they could get furthest away?
ys exactly.. charges in a conductor will always try to move away from each other as much as possible.. and in doing so they would always end up being on the surface .. :)
I would look into shell theory! If I remember correctly, that might be helpful!
Thanks! I'll look into shell theory too!
Join our real-time social learning platform and learn together with your friends!