Ask your own question, for FREE!
Mathematics 10 Online
OpenStudy (anonymous):

Calculate the area of triangle RST

OpenStudy (anonymous):

a.121 b.30.25 c.60.5 d.104.8

OpenStudy (jdoe0001):

notice in your triangle you have a 30 degree angle up above you also have a 90 degree angle at the bottom left what degree do you think is the other angle to the bottom right?

OpenStudy (anonymous):

60 on the right

OpenStudy (anonymous):

i tried using the 30 60 90 but i didn't get the answer

OpenStudy (jdoe0001):

hmm, what did you get for the SR side?

OpenStudy (jdoe0001):

using 30-60-90 rule that is

OpenStudy (anonymous):

Short Leg(2)= Hyp and Short Leg(sqrt3)=Long Leg

OpenStudy (jdoe0001):

right

OpenStudy (jdoe0001):

and you have the "shortest leg", so you can get the other leg right?

OpenStudy (jdoe0001):

keep in mind that ST = shortest leg = BASE SR = longer leg = altitude = height Area of a triangle = \(\bf \cfrac{1}{2}\times base \times height\)

OpenStudy (anonymous):

i got 121 sqrt 3

OpenStudy (jdoe0001):

hmmm |dw:1377808513502:dw| \(\bf Area =\cfrac{1}{2}\times base \times height \implies \cfrac{1}{2}\times 11 \times 11\sqrt{3} \implies \cfrac{121\sqrt{3}}{2}\)

OpenStudy (anonymous):

60.5?

OpenStudy (jdoe0001):

well, if you want a decimal figure, yes 121/2 = 60.5, you still have a \(\bf \sqrt{3}\) too btw

OpenStudy (anonymous):

:( i am lost...

OpenStudy (jdoe0001):

hmm, are you using Internet Explorer? if you don't mind me asking

OpenStudy (anonymous):

chrome

OpenStudy (jdoe0001):

ok... so . what ... part did you find confusing?

OpenStudy (jdoe0001):

\(\bf \cfrac{1}{2}\times \color{red}{base} \times \color{blue}{height} \implies \cfrac{1}{2}\times \color{red}{11} \times \color{blue}{11\sqrt{3}} \implies \cfrac{121\sqrt{3}}{2}\)

OpenStudy (anonymous):

like we ended up with 2 answers 60.5 and 121 but we also need the sqrt 3 i don't know what's the answer

OpenStudy (jdoe0001):

well, the answer would be \(\bf \cfrac{121\sqrt{3}}{2}\)

OpenStudy (anonymous):

so it's 121?

OpenStudy (jdoe0001):

because that's what you'd get from \(\bf \cfrac{1}{2}\times base \times height\)

OpenStudy (jdoe0001):

well, you can leave it as a fraction, or you can use \(\bf \cfrac{121\sqrt{3}}{2}\implies \cfrac{121}{2} \times \sqrt{3}\implies 60.5 \times \sqrt{3}\implies 60.5 \times 1.7320 \approx 10.4789\)

OpenStudy (jdoe0001):

hmm have a typo there one sec

OpenStudy (jdoe0001):

\(\bf \cfrac{121\sqrt{3}}{2}\implies \cfrac{121}{2} \times \sqrt{3}\implies 60.5 \times \sqrt{3}\implies 60.5 \times 1.7320 \approx 104.789\)

OpenStudy (anonymous):

okay then the final would be 104.8 (rounded)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!