Question

Please assist/walk through :) 2k(k-1)=k(2k+1)

Answer 1

2k(k-1)=k(2k+1)

start by expanding your brackets on either side of the equation. Simply multiply what outside the bracket by what is inside:

2k*k - 2k*1 = k*2k + k*1
\[2k^2-2k=2k^2 + k\]
then subtract \[2k^2\] from either side of the equation
This will leave you with
\[-2k=k\]
divide both sides of the equation by k

-2=1

and we already know that -2 cannot equal 1
Therefore we can conclude that
\[2k(k-1)\neq k(2k+1)\]

Answer 2

but when you subtracted 2k^2 what happened to the 2 exponent?

Answer 3

Can somebody answer this question also! ^

Answer 4

what do you mean "what happened to the 2 exponent?" it was totally subtracted out of both sides of the equation. similar to the following scenario:
if we have: x+5 = x+10x
we can subtract the positive x from both sides, this will leave us with
5=10x
does this make sense?
basically we have dropped the x from both sides of the equation so that both sides are still equal and simplified

Answer 5

okay let me just go back to the equation real quick and make sure I get what you're saying

Answer 6

OH I understandd! Thanks I appreciate it!