Question

Troubles with Polynomials (writing equation incoming)

Answer 1

\[\frac{ t }{ t+3 }+\frac{ 4t }{ t-3 }-\frac{ 18 }{ t ^{2}-9}\]

Answer 2

I have started on the bottom with \[\frac{ t \left( t-3 \right) }{\left( t+3 \right)\left( t-3 \right) }+\frac{ 4t \left( t+3 \right) }{ t-3\left( t+3 \right) }-\frac{ 18 }{ t ^{2}-9 }\]

Answer 3

Okay so whats the problem?

Answer 4

I guess when I work it out I am etting the wrong answer

Answer 5

I get that but are you trying to find t?

Answer 6

\[\frac{ t ^{2}-3+4t ^{2}+3-18 }{ t ^{2-9} }\]

Answer 7

no simplify

Answer 8

looks simplified to me.

Answer 9

just add t^2 and t^2

Answer 10

I do and still get the wrong answer when applying it to my homework, I can't seem to find my mistake

Answer 11

well add up all the number on the top.

Answer 12

I do I know the answer should be \[\frac{ 5t-6 }{ t-3 }\] when you add up the above you get \[\frac{ 5t^2-18 }{ t^2-9 }\]

Answer 13

looks good.

Answer 14

No becuase I am not getting the right answer

Answer 15

The top I just posted I know is the answer, but I cant find out how to get there from where I am

Answer 16

You distributed incorrectly. The term being multiplied by the parenthesis has to multiply by both terms inside.

Answer 17

?

Answer 18

\[t(t-3) = t^2-3t\]

Answer 19

Same problem with the middle term.

Answer 20

Ok so that makes is what t^2+9t-18 on top?

Answer 21

Not quite. Show me your distribution on the second term.

Answer 22

When I multiple them across like I have them on top I get this \[t ^{2}-3t+4t ^{2}+12t-18\]

Answer 23

Exactly. What is 4+1?

Answer 24

5t^2 >.<

Answer 25

Great. Please continue... :-)

Answer 26

You are only supposed to simplify, correct?

Answer 27

So the problem is now \[\frac{( t+3)(5t-6) }{ (t+3)(t-3) }\] the (t+3) cancel out making the problem \[\frac{ 5t-6 }{ t-3 }\]

Answer 28

Yes, that is the answer I got.

Answer 29

ty for finding my rewrite mistakes

Answer 30

Glad to help. I've made many of those mistakes myself.