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FREE MEDAL!! Let f(x) = x2 - 16. Find f-1(x) would it be the sqrt of x+16????
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This is where you would switch y and x and solve for y
I take the medal, I mean, is free as in free drinks, so hey why not
is it the sqrt of x+16?
\(\bf f(x) \implies \color{red}{y} = \color{blue}{x}^2-16\\ f^{-1}(x) \implies \color{blue}{x} = \color{red}{y}^2-16\)
hehe
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well \(\bf f^{-1}(x) \implies x = y^2-16 \implies x+16 = y^2\)
....
so, you still need to take square root on both sides
ok so that gives me the sqrt of x+16??????
ohh yeah,.... shoot I didn't read you well, yes, it does \(\bf f^{-1}(x) \implies x = y^2-16 \implies x+16 = y^2 \implies \sqrt{ x+16 } = y\)
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