Question

differentiate 5^x/(ln5)

Answer 1

\[\frac{ 5^x }{ \ln5 }\]

Answer 2

Quotient Rule: d/dx(f(x)/g(x)=gf'-fg'/g^2
So, d/dx= 5^\[(5^xlog(5)\log(x)-(1/x)5^x)/\log(x)^2\]

Answer 3

check ,please. It's not good to me.

Answer 4

we don't apply quotient rule since ln5 is a constant.

Answer 5

okay thanks so much :)

Answer 6

my fault thought said ln(x)

Answer 7

its just 5^x

Answer 8

okay, so then how do you solve it without the quotient rule?

Answer 9

d/dx (5^x)=ln(5)d^x
ln(5)5^x/ln(5) is 5^x

Answer 10

I just retype Standish's work
\[\left(\frac{5^x}{ln5}\right)'= \frac{1}{ln5} (5^x)'= \frac{1}{ln5} ln5 *5^x= 5^x\]

Answer 11

gotcha thanks :)