Question

How can I calculate w from following Equation:

\(cot(2w) = \large \frac{w}{2}\)

Answer 1

Please refresh question once..

Answer 2

@satellite73

Answer 3

just to check, you mean cot as in short for coth, the hyperbolic trig function?

Answer 4

cot = cotangent

right @waterineyes ?

Answer 5

Yes, it is Cotangent..

Answer 6

Ah, I see. We just have different terminology here in Australia. I've had a couple of embarrassing situations like this now. Afraid I can't help much then, sorry.

Answer 7

I thought Mathematics is same everywhere.. :)

Answer 8

mhm, same here?

Answer 9

@ganeshie8 @.Sam. @AravindG

Answer 10

Oh I meant I agree with you @waterineyes

Answer 11

Most are the same, just that some terminology differs from country to country. It's similar to having two different text books, they can sometimes have different names, shortcuts, symbols for functions.

Answer 12

Oh, cot and cotangent??

After all meaning is same buddy..

Here, we use
\(cos^{-1}\) and other uses Arccos like that..

Answer 13

So you want to solve for w, right?

Answer 14

I tried, but i couldn't seem to get it :/

Answer 15

Yes, @AravindG

Answer 16

1 approach would be the graphical method

Answer 17

I am thinking of the algebraic way.

Answer 18

Take your time..

Answer 19

I doubt that this might help...?
\[\cot(2w) = \frac{ w }{ 2 } \rightarrow \frac{ 1 }{ \tan(2w) } = \frac{ w }{ 2 }\]

Answer 20

@dan815 @Luigi0210

Answer 21

In what sense, it can help??

Answer 22

I do not know.

Answer 23

I am not able to separate w completely to one side. What I got is this :

\[\cot w-\tan w=2\cot2w\]
\[\cot w-\tan w=2(\dfrac{w}{2})=w\]

Answer 24

Wait a second ...Maybe you could form a quadratic in tan w or cot w from here and solve for it! I dont have time to work it here though..Best of luck!

Answer 25

Suppose if I have a scientific calculator, then how can I put this equation in that calculator to find the value of \(\omega\)??

Answer 26

@hartnn you are urgently required here..

Answer 27

Newton's Method

Answer 28

Hmmm, well \[
\cot (2w) = \frac{\cos(2w)}{\sin(2w)}
\]So it does come out to be: \[
2\cos(2w) = w\sin(2w)
\]
I don't see any definitive method here other than finding roots.

Answer 29

which topic does this belong...i guess, no algebraic methods applicable

Answer 30

have you tried in terms of cosine and sine?

Answer 31

omfg. Lol. i Just saw someone suggested that. I'm such a meatball.

Answer 32

I am not able to find it unless I use online calculators like wolfram alpha..

How will we eliminate w from the argument of cot??