\int { mg\cos { \theta } d\theta } =\int { mR\ddot { \theta } } d\theta
\[\int\limits { mg\cos { \theta } d\theta } =\int\limits { mR\ddot { \theta } } d\theta \]
integrate wrt theta ,theta dot and theta double dot. i will give medal .can aby body help.
What math is this? This looks really hard.
integration @asdfasdf54514
@satellite73
\[\int mg \cos \theta d\theta\] mg are constant with respect to theta, bring them out \[mg\int \cos \theta d\theta\] can you integrate it now? @CGGURUMANJUNATH
my question is can u integtate lhs and rhs wrt theta ? @ash2326
is it the original question ?
s
yes, you can do that
can u show me the steps or draw which ever is convenient to u @ash2326
the m's will cancel
\[\int\limits { mg\cos { \theta } d\theta } =\int\limits { mR\ddot { \theta } } d\theta\] \[mg\int \cos \theta d\theta=mR\int \ddot \theta d\theta\] We know that \[\frac{d}{d\theta} \dot \theta=\ddot \theta\] so \[mg\int \cos \theta d\theta=mR\dot \theta +C\] where C is constant, I think you can integrate the left side, can't you?
the dots are wrt to t or theta ?!
usually dots mean derivative with respect to time
ok @ash2326 u have integrated wrt theta right ?
can u integrate wrt theta dot.
yes, cause we have dtheta in the equation. No info about time
no
no information is given wrt time.
@CGGURUMANJUNATH are the dots mean derivative with respect to theta or with respect to time ?
theta @Coolsector
ok.
can u show me the steps plz @Coolsector
what steps ? if you say that the dots are with respect to theta then see the solution ash gave you
ok what ash has done wrt theta is fine ,can u integrate wrt theta dot.
@Coolsector
theta dot =\dot { \theta }
\[\dot { \theta } \]
i meant.
my question is can u integtate lhs wrt theta and rhs wrt theta dot ;is it possible to do that ?
you mean in case your original equation: mgcos(theta) = mR* (theta double dot ) ?
if so you cant integrate like this one side wrt to one varible and the other wrt to another
thank you very much @Coolsector @ash2326 and @UnkleRhaukus
anyway. i still cant get it. if dot means derivative with respect to theta then theta dot should be 1.
it is like taking the derivative of x wrt to x. and the second derivative would be 0.
it is like taking the derivative of x wrt to x.YES IT IS RIGHT, then theta dot should be 1. HOW @coolsector.
@Coolsector @ash2326 @UnkleRhaukus chech out the attachment.
sorry check not chech this was the actual problem .
well the derivative shold be with respect to time as @Coolsector sugessted.
ok.
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