Question

Help!

Answer 1

A charged particle of unit mass and unit charge moves with a velocity V=(8 i+6j)m/s in a magnetic field of B=2k T.Chose the correct alternatives.

Answer 2

The path of the particle maybe \(X^2+Y^2-4X-21=0\)
The path of the particle maybe \(x^2+y^2=25\)
The path of the particle maybe \(y^2+z^2=25\)
The time period of the particle will be 3.14s

Answer 3

@Vincent-Lyon.Fr

Answer 4

I am not sure but ASSUMING it traverse a circle then D is correct for sure and I am getting B too since radius = 5 (R=mv/qB) and using left hand rule i found that force will be in x and y axis only not Z so yeah just some observations not SURE

Answer 5

v = 10 m/s
R = 0.5 cm
T = 3.14 ms

Answer 6

i am getting R=5
and how do i find eqn of circle

Answer 7

Is B = 2000 T ?

You cannot find equation of the circle as the question does not specify the starting point. But you can say which answers CAN apply and which are false.

Answer 8

b k cap it is

Answer 9

\[\LARGE R=\frac{mv}{qB}=\frac{1 \times 10}{1 \times 2}\]