The shown net forms a regular square pyramid with all lateral and base edges the same length.find the following: @terenzreignz
welcome to os
got a slant height of\[\sqrt{3}\]
Hi @peoplesay1123. A Warm Welcome to OS.
im sorry thats way hard for me :(
np
Okay... show me what you've done so far...
well i got the slant height as \[\sqrt{3}in.\] and i got the perimeter of the base as 8 in. and the base area as 4 in^2 and idk if any of those are correct but thats all i could came up with. Then i had the Lat area as about 6.93 in^2 and the surface area as 10.93 in^2. I think some of it is wrong though idk.
I posted the attachment for the diagram of this problem in these comments, just so u know.
Remember, those triangles at the side are equilateral triangles...
yea
Well, I vividly remember telling you the formula for the area of an equilateral triangle yesterday... we even derived it. Did you pay attention? :P
yeah i remember that but how do i use that formula to find thae slant height and base perimeter and base area and lat area.
Don't worry, your slant height, base perimeter and base area are correct.
isnt the formula for a the lat area of a regular pyramid 1/2(perimeter of base)(slant height)
?
I suppose. Yes, that's right. Work that out, you get...?
about 6.93 in.^2
Nope... try again... or you could show me how you got that...
1/2(8)(sqr root of 3)= 4(sqr root of 3)= 6.928= 6.93
ahh... the base length is 2, not 8.
but isnt the formula 1/2Pl ?
not 1/2Bl
Oh... sorry, right. I thought it was just one face. Then it's right, what you did ^_^
oh ok and the surface area is about 10.93 .
?
Right. did you actually need help with this? ^_^
oh i guess i wanted to make sure. Because if you look at the diagram it show Lateral Area= and i thought i was not getting the right answer becuase my lateral area didnt EQUAL 6.93 it was ABOUT 6.93. so wouldnt i use
\[\approx \]
and not>>> =
Whatever floats your (or your instructor's) boat, I assume. And lol, that sign looks fancier XD
oh alright i guess it dosent matter then its all the same i guess.. thanks for the reassuring help lol
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