Given the functions f(n) = 25 and g(n) = 3(n − 1), combine them to create an arithmetic sequence, an, and solve for the 12th term.
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OpenStudy (anonymous):
@ivettef365
OpenStudy (anonymous):
an = 25 − 3(n − 1); a12 = −11
an = 25 − 3(n − 1); a12 = −8
an = 25 + 3(n − 1); a12 = 58
an = 25 + 3(n − 1); a12 = 61
OpenStudy (anonymous):
@ivettef365
OpenStudy (anonymous):
@satellite73
OpenStudy (ivettef365):
If I have to guess I would go for the 3rd option
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OpenStudy (anonymous):
thanksss :)
OpenStudy (anonymous):
Given an arithmetic sequence in the table below, create the explicit formula and list any restrictions to the domain.
OpenStudy (anonymous):
OpenStudy (ivettef365):
ok, on 4, you have that term 1 = 40, the other terms are greater
so n>=40
OpenStudy (ivettef365):
now if you plug term 2, on option 1which is
an = 40 + 7(n − 1) let see if it works, term 2
40 + 7(2-1)
40 + 7(1)
40 + 7 = 47 that is correct term 2 is 47
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OpenStudy (ivettef365):
did you understand ?
OpenStudy (anonymous):
ohh ok
OpenStudy (anonymous):
So the full answer would then be an = 40 + 7(n − 1) where n ≥ 1 (just took the test!).
:)
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