Question

why 0! and 1! both are equal to one

Answer 1

Because we have this identity :)
\[\Large n! = n\cdot (n-1)!\]
So, by that logic, we have:
\[\Large 1! = 1(1-1)!\]
\[\Large 1 = 1\cdot0!\]

Answer 2

Implying that 0! = 1

Answer 3

ok....
BUT HOW 0! is = to 1

Answer 4

Okay... THIS
\[\Large n!= n(n-1)!\] is true, right?
Just take n = 1.

Answer 5

You pretty much just have to accept it.

It simplifies very complex concepts

Answer 6

\[\Large 1! = 1\cdot(1-1)!\]
Now, we know that 1! = 1
\[\Large 1 = 1\cdot 0!\]
Now, solving for 0! does yield
\[\Large 0! = 1\]

Answer 7

ok..thank you