Will I actually get an answer on this one? Or will I wait for nothing like last question! A 5 mile cab ride cost 7.20 a 9 mile cab ride cost 11.60 find a linear equation that models a relationship between cost c and distance d A. c=1.44d+4.40 B. d=1.10c+4.40 C. c=1.29d+1.70 D. c=1.10d+1.70
The distance d is equivalent to the x variable, and the cost c is equivalent to the y variable. So we can find the slope from the ordered pairs (5, 7.2) and (9, 11.6). Are you with me?
yes
\[m=\frac{11.6-7.2}{9-5}=you\ can\ calculate\]
2.4
Not really. The numerator simplifies to 4.4 and the denominator simplifies to 4. What did you get?
\[m=\frac{11.6-7.2}{9-5}=\frac{4.4}{4}=?\]
1.4
its a correct
No. m = 4.4/4 = 1.1 Now we have a value for m, the linear equation can be written as: c = 1.10d + b where b is a constant that needs to be found by substition as follows: 7.2 = (1.10 * 5) + b ........(1) Can you solve equation (1) tnd the value of b ?
substitution*
I got d
Well you can find that d is the correct choice without finding the value of the constant. But you will learn more by finding the value of b.
We have two points (5, 7.20) and (9, 11.60) So use the slope formula to get m = (y2-y1)/(x2-x1) m = ( 11.60- 7.20)/(9-5) m = (4.4)/4 m = 1.1 So the slope of the line that passes through the two points is 1.1
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