Question

Find the slope of the tangent line to the curve


4 x^2 -2 xy + 2 y^3 = 94


at the point ( 4,3 )

Answer 1

\[find \frac{ dy }{ dx } and then plugx=4,y=3\]

Answer 2

thanks!

Answer 3

yw

Answer 4

wait, i keep getting it wrong...:(
@surjihayer

Answer 5

is this the derivative?
8x-2y'+6yy'=0?
@Hero

Answer 6

\[8x-2\left( xy \prime+1y \right)+6y ^{2}y \prime =0\]
\[\left( -2x+6y ^{2} \right)y \prime =-8x+2y\]
\[y \prime=\frac{ 2y-8x }{ 6y ^{2}-2x }=\frac{ y-4x }{3y ^{2}-x }\]
now plug the values.

Answer 7

i cant read that, is it different from my answer?

Answer 8

yes

Answer 9

\[\frac{ d }{dx }\left( xy \right)=x \frac{ dy }{ dx}+1y\]

Answer 10

\[\frac{ d }{ dx}\left( 2y ^{3} \right)=2*3 y ^{2}\frac{ dy }{dx }\]

Answer 11

\[\frac{ d }{dx }\left( xy \right)=x \frac{ dy }{ dx}+1y\]

Answer 12

yes