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Mathematics 22 Online
OpenStudy (anonymous):

Find the inverse

OpenStudy (zzr0ck3r):

ok?

OpenStudy (anonymous):

\[f(x)=\frac{ 1+5x }{ 7-3x }\]

OpenStudy (debbieg):

Change the f(x) to y, then swap your x's and your y (e.g., write a y in place of each x, and and x in place of the y) Then solve for y.

OpenStudy (anonymous):

okay. stay so I can check with you

OpenStudy (anonymous):

okay so I have \[-3^{2}+2y-1=0\]

OpenStudy (anonymous):

am I on the right track?

OpenStudy (zzr0ck3r):

\[y=\frac{1+5x}{7-3x}\] as @DebbieG said switch the x's and y's \[x=\frac{1+5y}{7-3y}\] solve for y\[x(7-3y)=1+5y\\7x-3xy=1+5y\\7x-1=3xy+5y\\y(3x+5)=7x-1\\y=\frac{7x-1}{3x+5}\]

OpenStudy (debbieg):

sorry, I was in another tab. Well, no, I'm not sure where you came up with that. @zzr0ck3r shows you how to do it above.

OpenStudy (anonymous):

thanks guys

OpenStudy (zzr0ck3r):

np

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