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Find the inverse
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ok?
\[f(x)=\frac{ 1+5x }{ 7-3x }\]
Change the f(x) to y, then swap your x's and your y (e.g., write a y in place of each x, and and x in place of the y) Then solve for y.
okay. stay so I can check with you
okay so I have \[-3^{2}+2y-1=0\]
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am I on the right track?
\[y=\frac{1+5x}{7-3x}\] as @DebbieG said switch the x's and y's \[x=\frac{1+5y}{7-3y}\] solve for y\[x(7-3y)=1+5y\\7x-3xy=1+5y\\7x-1=3xy+5y\\y(3x+5)=7x-1\\y=\frac{7x-1}{3x+5}\]
sorry, I was in another tab. Well, no, I'm not sure where you came up with that. @zzr0ck3r shows you how to do it above.
thanks guys
np
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