which statement is true? all irrational numbers are also rational numbers irrational numbers cannot be classified as rational numbers
Rational and irrational numbers are opposites. You were given a link to wikipedia earlier, you really should read it.
what the hell I blocked you any ways
i think this is a reading comprehension problem math is weird, but it is not that weird how could an "irrational" number also be "rational"?
i have no idea right it cant be both
You blocked me? No problem. I'll try to remember not to answer anymore questions from you.
thank god you don't even answer them anyways you just send me somewhere else
Well, I know that "all irrational numbers are also rational numbers" Is false. A counterexample to this would be "The Euler Mascheroni constant" defined as: \[\int^\infty_1{\left(\frac{1}{\lfloor{x}\rfloor}-\frac{1}{x}\right)}\phantom{0}dx\]
And since "If either a or b is true and a is false, therefore b must be true" I guess, irrational numbers cannot be classified as rational numbers
Holy cr@p, can't we just use \(\sqrt{2}\) as a counterexample?? LOL!
thank you so much so irrational numbers cannot be classified as rational numbers
right
thanks to everyone that helped me ..
that is why they are called "irrational" i.e. "not rational"
brain fart right. i read it and reread that stupid question and walked away i got it . with your guys help thanks
Haha, well in a sense, \(\sqrt{2}=\frac{2}{\sqrt{2}}\) I considered using \(e\) but then I thought that \[e=\frac{1}{0!}+\frac{1}{1!}+\frac{1}{2!}+\frac{1}{3!}+\frac{1}{4!}...\] And realized I wanted a more, less rational strong counterexample lol
lol
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