Question

Half the supplement of an angle is 18 degrees less than four times the complement of the angle. Set up and solve an equation to find the measure of the angle, the complement, and supplement.

Answer 1

Let x = the angle
then 180-x= supplement and
90-x = complement.

Answer 2

so far the equation I have is 1/2(18)-x=4(90-x)+18 is that right?

Answer 3

@mertsj

Answer 4

180 and 18

Answer 5

\[\frac{1}{2}(180-x)=4(90-x)-18\]

Answer 6

x=84 ?

Answer 7

@mertsj

Answer 8

x=72

Answer 9

how did you get that?

Answer 10

Just tell us how you've got 84

Answer 11

1/2(180)-x=4(90-x)-18 -->>
90-x=360-4x-18
+4x +4x
90+3x=342
-90 -90
3x=252
x=84

Answer 12

where do i go wrong

Answer 13

You forgot to divide the x to 2 in the left side of the eq'n.
It should be 90- (x/2) = 4(90-x)- 18

But I have a simpler solution, maybe you can solve that easier.

Answer 14

i dont understand exactly so it would be 90-(x/2)=342-4x

Answer 15

wait ok i get it now

Answer 16

so complement is 18
supplement is 108

Answer 17

it says here that the half of the supplement, which is 1/2 (180-x) is equal to 18 deg less than four times of its complement which in symbols will be equal to 4(90-x)-18
You get it?

Answer 18

54

Answer 19

How you come up to 54? Do you want me to show my solution?

Answer 20

yes cause i cant get it

Answer 21

\[(1/2) (180-x) = 4(90-x) - 18\]
\[(1/2) (180-x) = 360 - 4x - 18\]
\[(1/2) (180 - x) = 342 - 4x\]
\[180-x = 684 - 8x\]
Therefore,
\[ 7x = 504\]
x = 72

Answer 22

yes i got that part which is the angle, but i also need to find the supplement and complement but for that do i just replace x with 72 thats how i got 54

Answer 23

Well, it's still not 54.
The complement is just 90-x and the supplement is just 180-x

Answer 24

18 & 108

Answer 25

Nice. You got it right now! :D

Answer 26

thanks, im bad at math so it takes awhile. but thank you for all your help